uh it should be in kgs sorry, I was just bewildered how I managed to fuck up an equation with it literally being in front of me (cus I googled it). The number comes up to a little less than 2 protons… which means (according to my food poisoned brain’s calculation) that if there were 2 protons in a sphere with a radius of 15 cm, it would collapse into a black hole.
So you’re saying that 2 protons closer than 15 cm would collapse into a black hole? That’s got me pretty worried, because I have a lot more than 2 protons within that proximity in my body, by at least an order of magnitude or so
Alright mate, you and I seem to be having a major problem with communication. I am not trying to see how much I would have to squeeze a normal cat to form a blackhole, I am trying to see how much a cat would have to weigh to form a blackhole as it curled up. And an equation can be used to find any component of said equation as long it is the only one missing, so there is no one thing I “have to do”. I am really feeling like you’re disrespecting me here.
I always thought that leaving a conversation unfinished was a rude thing. What I was trying to find (as I have previously said) is how much a cat would have to weigh to collapse into a blackhole (assuming the cat when curled up would resemble a sphere with a radius of 15 cm). Last thing, how is “a more common problem” any helpful? I appreciate you trying to help but it feels like telling somebody, who is drowning, that breathing air instead of water would prevent drowning. Again, thank you for trying to be helpful.
(no one does … he doesn’t say if that’s a number of ounces or a number of metric tons …)
uh it should be in kgs sorry, I was just bewildered how I managed to fuck up an equation with it literally being in front of me (cus I googled it). The number comes up to a little less than 2 protons… which means (according to my food poisoned brain’s calculation) that if there were 2 protons in a sphere with a radius of 15 cm, it would collapse into a black hole.
So you’re saying that 2 protons closer than 15 cm would collapse into a black hole? That’s got me pretty worried, because I have a lot more than 2 protons within that proximity in my body, by at least an order of magnitude or so
yeah sorry, its all blackholes now
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is density not just weight divided by volume? I had a set volume (assumed the cat was a sphere with a radius of 15 cm), where am I wrong…
And yes the calculation is wrong, that was the point, I WAS TRYING TO BE FUNNY.
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Alright mate, you and I seem to be having a major problem with communication. I am not trying to see how much I would have to squeeze a normal cat to form a blackhole, I am trying to see how much a cat would have to weigh to form a blackhole as it curled up. And an equation can be used to find any component of said equation as long it is the only one missing, so there is no one thing I “have to do”. I am really feeling like you’re disrespecting me here.
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I always thought that leaving a conversation unfinished was a rude thing. What I was trying to find (as I have previously said) is how much a cat would have to weigh to collapse into a blackhole (assuming the cat when curled up would resemble a sphere with a radius of 15 cm). Last thing, how is “a more common problem” any helpful? I appreciate you trying to help but it feels like telling somebody, who is drowning, that breathing air instead of water would prevent drowning. Again, thank you for trying to be helpful.
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